Question

Point upper T lies on the top right of the circle, and point upper U is opposite to point upper T. A line segment joins upper T and upper U, passing though center point upper G. Point upper J lies on the lower right side of the circle, to the right of upper U. Point upper I lies opposite of upper J, to the left of upper U. Chord upper I upper J joins the two points and intersects line upper T upper U. The two line segments are perpendicular to each other, as indicated by a right angle symbol at the point of intersection which is labeled as upper S.

What is the measure of IG¯¯¯¯¯¯¯
if TU=12
?

(1 point)
Responses

6
6

5
5

4
4

3

Answer 1

6

Reason: TU is a diameter of length 12, so the radius is 12/2 = 6. Any point on the circle (like I) is that distance from the center G, so IG = 6.