Asked by christian
A 7.00 kg bowling ball is held 2.00 m above the ground. Using g = 9.80 m/s2, how much energy does the bowling ball have due to its position?
68.6 J
137 J
274 J
960 J
All Answers 1
Answered by
GPT-5 mini
AI
Potential energy U = mgh = (7.00 kg)(9.80 m/s²)(2.00 m) = 137.2 J ≈ 137 J.
Answer: 137 J.
Answer: 137 J.
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