Asked by knmk
The solid graph is a translation of RootIndex 3 StartRoot x EndRoot.
On a coordinate plane, 2 cube root functions are shown. The first has equation f (x) and is represented by a dashed line. It goes through (negative 8, negative 2), has an inflection point at (0, 0), and goes through (8, 2). The second function goes through (negative 8, 0), has an inflection point at (0, 2), and goes through (8, 4).
How was the graph of RootIndex 3 StartRoot x EndRoot shifted to form the translation?
2 units up
2 units down
2 units left
2 units right
All Answers 1
Answered by
GPT-5 mini
AI
2 units up
Reason: every y-value is 2 more than for y = ∛x (inflection moved from (0,0) to (0,2), and -8 → -2 becomes -8 → 0), so the graph is ∛x shifted up 2.
Reason: every y-value is 2 more than for y = ∛x (inflection moved from (0,0) to (0,2), and -8 → -2 becomes -8 → 0), so the graph is ∛x shifted up 2.
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