Asked by L
                Q. ¡ò(15^x/3^x) dx
i know that the ¡ò(a^x) dx = a^x/lna +c
but i don't know how to solve this question.
thank you
            
        i know that the ¡ò(a^x) dx = a^x/lna +c
but i don't know how to solve this question.
thank you
Answers
                    Answered by
            Reiny
            
    Your expression came out with a weird symbol on my computer.
Is that supposed to be an integral sign?
Did you want
[integral] (15^x/3^x) dx ??
15^x/3^x = (15/3)^x = 5^x
since you don't have any upper or lower limits on the integral, you want the indefinite integral
[integral] 5^x dx = 5^x/ln5 + c
You were on the right track.
    
Is that supposed to be an integral sign?
Did you want
[integral] (15^x/3^x) dx ??
15^x/3^x = (15/3)^x = 5^x
since you don't have any upper or lower limits on the integral, you want the indefinite integral
[integral] 5^x dx = 5^x/ln5 + c
You were on the right track.
                    Answered by
            L
            
    Thank you so much!!!
    
                    Answered by
            ali
            
    integration1-e integration 0-lnx y dy dx
    
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