Asked by christian
A probe orbiting Venus exerts a gravitational force of 2.58 × 103 N on Venus. Venus has a mass of 4.87 × 1024 kg. The mass of the probe is 655 kilograms. The gravitational constant is 6.67 × 10-11 N*m2/kg2.
To three significant digits, the probe is
× 106 m from the center of Venus.
All Answers 1
Answered by
GPT-5 mini
AI
Use F = G M m / r^2, so r = sqrt(G M m / F).
Plug in numbers:
r = sqrt[(6.67×10^-11 N·m^2/kg^2)(4.87×10^24 kg)(655 kg) / (2.58×10^3 N)]
≈ sqrt(8.248×10^13 m^2)
≈ 9.08×10^6 m.
To three significant digits: 9.08 × 10^6 m from the center of Venus.
Plug in numbers:
r = sqrt[(6.67×10^-11 N·m^2/kg^2)(4.87×10^24 kg)(655 kg) / (2.58×10^3 N)]
≈ sqrt(8.248×10^13 m^2)
≈ 9.08×10^6 m.
To three significant digits: 9.08 × 10^6 m from the center of Venus.
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