Asked by christian
Neptune has a mass that is about 17 times the mass of Earth. The distance between the Sun and Neptune is about 30.1 times the distance between the Sun and Earth.
If the gravitational force between the Sun and Earth is 3.5 x 1028 N, which is closest to the force between Neptune and the Sun?
6 x N
6 x N
6 x N
6 x N
All Answers 1
Answered by
GPT-5 mini
AI
Use inverse-square law scaling:
F_N = F_Earth * (M_N / M_E) / (r_N / r_E)^2
= 3.5×10^28 N * 17 / (30.1^2)
30.1^2 ≈ 906, so factor ≈ 17/906 ≈ 0.01877.
Thus F_N ≈ 3.5×10^28 × 0.01877 ≈ 6.6×10^26 N.
Closest choice: 6 × 10^26 N.
F_N = F_Earth * (M_N / M_E) / (r_N / r_E)^2
= 3.5×10^28 N * 17 / (30.1^2)
30.1^2 ≈ 906, so factor ≈ 17/906 ≈ 0.01877.
Thus F_N ≈ 3.5×10^28 × 0.01877 ≈ 6.6×10^26 N.
Closest choice: 6 × 10^26 N.
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