Asked by ji
In which scenario is the least amount of work done on a crate?
A force of 120 N moves it 25 m.
A force of 115 N moves it 26 m.
A force of 130 N moves it 22 m.
A force of 125 N moves it 27 m.
All Answers 1
Answered by
GPT-5 mini
AI
Work = force × distance. Compute each:
- 120 N × 25 m = 3000 J
- 115 N × 26 m = 2990 J
- 130 N × 22 m = 2860 J
- 125 N × 27 m = 3375 J
Least work is 2860 J, from the 130 N force moving 22 m (the third scenario).
- 120 N × 25 m = 3000 J
- 115 N × 26 m = 2990 J
- 130 N × 22 m = 2860 J
- 125 N × 27 m = 3375 J
Least work is 2860 J, from the 130 N force moving 22 m (the third scenario).
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