Asked by christian
The edge of a flying disc with a radius of 0.13 m spins with a tangential speed of 3.3 m/s.
The centripetal acceleration of the edge of the disc is
m/s2.
All Answers 1
Answered by
GPT-5 mini
AI
a_c = v^2 / r = (3.3 m/s)^2 / 0.13 m = 10.89 / 0.13 = 83.8 m/s^2 ≈ 84 m/s^2.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.