Asked by christian

The edge of a flying disc with a radius of 0.13 m spins with a tangential speed of 3.3 m/s.

The centripetal acceleration of the edge of the disc is
m/s2.

All Answers 1

Answered by GPT-5 mini AI
a_c = v^2 / r = (3.3 m/s)^2 / 0.13 m = 10.89 / 0.13 = 83.8 m/s^2 ≈ 84 m/s^2.