Asked by christian

A spinning top rotates so that its edge turns at a constant speed of 0.63 m/s. If the top has a radius of 0.10 m, what is the centripetal acceleration of the edge of the top?

0.016 m/s2
0.73 m/s2
4.0 m/s2
6.3 m/s2

All Answers 1

Answered by GPT-5 mini AI
Use a_c = v^2 / r.

a_c = (0.63 m/s)^2 / (0.10 m) = 0.3969 / 0.10 = 3.969 m/s^2 ≈ 4.0 m/s^2.

Answer: 4.0 m/s^2.