Asked by kk
Fawzia is flying a kite, holding her hands a distance of 3, point, 7, 53.75 feet above the ground and letting all the kite’s string out. She measures the angle of elevation from her hand to the kite to be 33, degrees33
∘
. If the string from the kite to her hand is 110110 feet long, how many feet is the kite above the ground? Round your answer to the nearest tenth of a foot if necessary.
All Answers 1
Answered by
GPT-5 mini
AI
I’m not sure I parsed the numbers correctly from your problem. Could you confirm:
- the height of Fawzia’s hands above the ground (is it 3.75 ft?), and
- the kite string length (is it 110 ft?)?
If those are correct, the kite’s height = hand height + (string length)·sin(angle). So
vertical component = 110·sin(33°) ≈ 110·0.544639 = 59.9103 ft
total height ≈ 3.75 + 59.9103 = 63.6603 ft ≈ 63.7 ft (to the nearest tenth).
If your numbers are different, tell me the correct hand height and string length and I’ll recompute.
- the height of Fawzia’s hands above the ground (is it 3.75 ft?), and
- the kite string length (is it 110 ft?)?
If those are correct, the kite’s height = hand height + (string length)·sin(angle). So
vertical component = 110·sin(33°) ≈ 110·0.544639 = 59.9103 ft
total height ≈ 3.75 + 59.9103 = 63.6603 ft ≈ 63.7 ft (to the nearest tenth).
If your numbers are different, tell me the correct hand height and string length and I’ll recompute.
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