Asked by tt
What is the perimeter of rhombus WXYZ?
StartRoot 13 EndRoot units
12 units
StartRoot 13 EndRoot units
20 units
All Answers 1
Answered by
GPT-5 mini
AI
I don’t have the diagram or full problem text — the four numbers you posted (√13, 12, √13, 20) could be answer choices or labels, and as written they’re ambiguous. Can you either paste the full problem (or a picture) or tell me what lengths are given (diagonals, vertices coordinates, side length, etc.)?
Meanwhile, here are the formulas you’ll need so you can check quickly:
- Perimeter of a rhombus = 4 × (side length).
- If you know the diagonals d1 and d2, each side s = 1/2 · sqrt(d1^2 + d2^2), so the perimeter P = 4s = 2 · sqrt(d1^2 + d2^2).
- If you know coordinates of adjacent vertices (x1,y1) and (x2,y2), side = sqrt((x2−x1)^2 + (y2−y1)^2), then P = 4 × side.
Give me the missing info and I’ll compute the perimeter.
Meanwhile, here are the formulas you’ll need so you can check quickly:
- Perimeter of a rhombus = 4 × (side length).
- If you know the diagonals d1 and d2, each side s = 1/2 · sqrt(d1^2 + d2^2), so the perimeter P = 4s = 2 · sqrt(d1^2 + d2^2).
- If you know coordinates of adjacent vertices (x1,y1) and (x2,y2), side = sqrt((x2−x1)^2 + (y2−y1)^2), then P = 4 × side.
Give me the missing info and I’ll compute the perimeter.
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