Question

A business recorded its yearly profits since 1990. In the table, x
represents the years since 1990, and y
represents the profit in millions of dollars.

Evaluating the quadratic function using the given x and y values.
x
0 2 3 5 8 11
y
5.7 4.9 4.8 5.2 7.3 11.2
Find the quadratic function that best models the data and use it to find the business's profit in the year 2010.

(1 point)
Responses

f(x)=0.14x2−0.94x+5.93
; The profit in the year 2010 is $43,130,000.
f left parenthesis x right parenthesis equals 0.14 x squared minus 0.94 x plus 5.93 ; The profit in the year 2010 is $43,130,000.

f(x)=0.1x2−0.6x+5.7
; The profit in the year 2010 is $77,700,000.
f left parenthesis x right parenthesis equals 0.1 x squared minus 0.6 x plus 5.7 ; The profit in the year 2010 is $77,700,000.

f(x)=0.1x2−0.6x+5.7
; The profit in the year 2010 is $33,700,000.
f left parenthesis x right parenthesis equals 0.1 x squared minus 0.6 x plus 5.7 ; The profit in the year 2010 is $33,700,000.

f(x)=0.14x2−0.94x+5.93
; The profit in the year 2010 is $103,730,000.
span widget f of x is equal to 0 point 1 4 x squared minus 0 point 9 4 x plus 5 point 9 3 ; The profit in the year 2010 is $103,730,000.

Answer 1

The best-fit quadratic is f(x) = 0.1x^2 − 0.6x + 5.7. For 2010, x = 20, so f(20) = 0.1(20)^2 − 0.6(20) + 5.7 = 33.7 million dollars = $33,700,000.