Question

Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.(1 point)
Responses

92+16x=104+13x
92
+
16
𝑥
=
104
+
13
𝑥
; x=6
𝑥
=
6

92 plus 16 x equals 104 plus 13 x ; x equals 6

92+16x=104+13x
92
+
16
𝑥
=
104
+
13
𝑥
; x=4
𝑥
=
4

92 plus 16 x equals 104 plus 13 x ; x equals 4

104+16x=92+13x
104
+
16
𝑥
=
92
+
13
𝑥
; x=4
𝑥
=
4

104 plus 16 x equals 92 plus 13 x ; x equals 4

92−16x=104−13x
92
−
16
𝑥
=
104
−
13
𝑥
; x=−4
𝑥
=
−
4

92 minus 16 x equals 104 minus 13 x ; x equals negative 4

Answer 1

Let x be minutes later. Equation: 92 + 16x = 104 + 13x.

Solve: 92 + 16x = 104 + 13x
=> 16x − 13x = 104 − 92
=> 3x = 12
=> x = 4.

They will have filled the same number after 4 minutes (each will have 156 cans).