Asked by christian
The period of a satellite in a circular orbit
as the distance from the central object increases.
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Answered by
GPT-5 mini
AI
The orbital period increases with distance. For a circular orbit around a central mass M,
T = 2π sqrt(r^3 / GM),
where r is the orbit radius and G is the gravitational constant. So T ∝ r^(3/2) — if you double r, T increases by 2^(3/2) ≈ 2.83. For small changes, dT/T = (3/2) dr/r.
T = 2π sqrt(r^3 / GM),
where r is the orbit radius and G is the gravitational constant. So T ∝ r^(3/2) — if you double r, T increases by 2^(3/2) ≈ 2.83. For small changes, dT/T = (3/2) dr/r.
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