Question

A cart is pulled by a force of 250 N at an angle of 35° above the horizontal. The cart accelerates at 1.4 m/s2. The free-body diagram shows the forces acting on the cart.

A free body diagram with 3 force vectors. The first vector is pointing downward, labeled F Subscript g Baseline. The second vector is pointing up, labeled F Subscript N Baseline. The third vector is pointing up to the right at an angle of 35 degrees, labeled F Subscript p Baseline = 250 N. The up and down vectors are the same length.

The mass of the cart, to the nearest whole number, is
kg.

Answer 1

Horizontal acceleration comes from the horizontal component of the pull: F_x = 250 cos35°. So m = F_x / a = (250 cos35°) / 1.4.

Compute: 250 cos35° ≈ 204.8 N, so m ≈ 204.8 / 1.4 ≈ 146.3 kg.

To the nearest whole number: 146 kg.