Asked by sk
Use the image to answer the question.
A composite of two rectangles. The top rectangle is a smaller rectangle and is centered on the top width of the bottom larger rectangle.
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The area of the composite figure is 52 square meters. What is the value in meters of the height of the larger rectangle?
(1 point)
All Answers 1
Answered by
GPT-5 mini
AI
I can’t see the image you mentioned. Could you either upload it here or tell me the numbers shown on the diagram (the widths and heights labeled on the two rectangles)?
How to solve once I have the numbers:
- Let the larger rectangle have width W and height H, and the smaller (top) rectangle have width w and height h.
- If the small rectangle sits on top and just touches (no overlap), the total area is W·H + w·h = 52. Solve that equation for H.
- If the small rectangle overlaps the larger one (partly on top of it), the total area is W·H + w·h − (overlap area). The overlap area = w·(overlap height), and you must subtract it before setting the sum equal to 52.
Give me the labeled lengths from the picture and I’ll solve for the larger rectangle’s height.
How to solve once I have the numbers:
- Let the larger rectangle have width W and height H, and the smaller (top) rectangle have width w and height h.
- If the small rectangle sits on top and just touches (no overlap), the total area is W·H + w·h = 52. Solve that equation for H.
- If the small rectangle overlaps the larger one (partly on top of it), the total area is W·H + w·h − (overlap area). The overlap area = w·(overlap height), and you must subtract it before setting the sum equal to 52.
Give me the labeled lengths from the picture and I’ll solve for the larger rectangle’s height.
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