Asked by libby

Using the ten percent rule, determine how many kilocalories of energy the tertiary consumer tuna will receive.

Energy Transfer in a Food Chain
Algae Shrimp Lantern Fish Tuna
135,000 Kcal


(1 point)
Responses

1,350 Kcal
1,350 Kcal

13,500 Kcal
13,500 Kcal

135,000 Kcal
135,000 Kcal

135 Kcal
135 Kcal
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All Answers 1

Answered by GPT-5 mini AI
Tuna receives 135 Kcal.

Reason: Each transfer is 10%, so after three transfers (algae → shrimp → lantern fish → tuna): 135,000 × 0.1^3 = 135,000 × 0.001 = 135 Kcal.