Asked by QuestionHelper123
For how many jerseys would it be better (less expensive) to choose Print It?
*
1 point
5 Jerseys
10 Jerseys
Any amount more than 15 jerseys
Any amount less than 15 jerseys
Print It will always be a better deal no matter how many jerseys you order.
Print It will never be a better deal.
All Answers 1
Answered by
GPT-5 mini
AI
I don’t have the pricing info from the original problem, so I can’t pick one of those choices yet. Give me the cost formulas (or the per-jersey and any flat/setup fees) and I’ll solve it.
How to decide (so you can check quickly):
- Let PrintIt cost = P(n) = a*n + A (a = per-jersey, A = flat fee).
- Let the other option cost = Q(n) = b*n + B.
- Solve P(n) < Q(n): (a − b)n < B − A.
- If a − b > 0 then n < (B − A)/(a − b).
- If a − b < 0 then n > (B − A)/(a − b).
- If a − b = 0 then compare A and B (one with smaller flat fee is always cheaper, or they’re equal).
Example: if PrintIt = $8 per jersey + $20 setup and Other = $10 per jersey + $0 setup, then
8n + 20 < 10n → 20 < 2n → n > 10, so PrintIt is better for more than 10 jerseys.
Send the two prices and I’ll compute which answer choice is correct.
How to decide (so you can check quickly):
- Let PrintIt cost = P(n) = a*n + A (a = per-jersey, A = flat fee).
- Let the other option cost = Q(n) = b*n + B.
- Solve P(n) < Q(n): (a − b)n < B − A.
- If a − b > 0 then n < (B − A)/(a − b).
- If a − b < 0 then n > (B − A)/(a − b).
- If a − b = 0 then compare A and B (one with smaller flat fee is always cheaper, or they’re equal).
Example: if PrintIt = $8 per jersey + $20 setup and Other = $10 per jersey + $0 setup, then
8n + 20 < 10n → 20 < 2n → n > 10, so PrintIt is better for more than 10 jerseys.
Send the two prices and I’ll compute which answer choice is correct.
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