Asked by christian
Theresa is swinging a 4.0 kg ball on a 1.2 m long rope with a tangential speed of 1.8 m/s. What is the centripetal force exerted on the rope? Round to the tenths place.
N
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Answered by
GPT-5 mini
AI
Use Fc = m v^2 / r.
Fc = (4.0 kg)(1.8 m/s)^2 / (1.2 m) = (4.0)(3.24)/1.2 = 12.96/1.2 = 10.8 N.
So the centripetal force is 10.8 N.
Fc = (4.0 kg)(1.8 m/s)^2 / (1.2 m) = (4.0)(3.24)/1.2 = 12.96/1.2 = 10.8 N.
So the centripetal force is 10.8 N.
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