Question

A baseball is launched horizontally from a height of 1.8 m. The baseball travels 0.50 m before hitting the ground.

How fast is the baseball moving horizontally, rounded to the nearest hundredth?
m/s

Answer 1

Time to fall: t = sqrt(2h/g) = sqrt(2(1.8)/9.8) ≈ 0.606 s.

Horizontal speed: v = x/t = 0.50 / 0.606 ≈ 0.825 m/s ≈ 0.83 m/s (to the nearest hundredth).