Asked by jhdsuzfh
From a height of 3,000 feet, a falcon descends at a rate of 250 ft./sec. What is the rate of change in the falcon’s elevation, and what is the initial value? (1 point)
Responses
The rate of change is 250 ft./sec., and the initial value is 3,000 ft.
The rate of change is 250 ft./sec., and the initial value is 3,000 ft.
The rate of change is 3,000 ft./sec., and the initial value is −250
−
250
ft.
The rate of change is 3,000 ft./sec., and the initial value is negative 250 ft.
The rate of change is 3,000 ft./sec., and the initial value is 250 ft.
The rate of change is 3,000 ft./sec., and the initial value is 250 ft.
The rate of change is −250
−
250
ft./sec., and the initial value is 3,000 ft.
The rate of change is negative 250 ft./sec., and the initial value is 3,000 ft.
All Answers 1
Answered by
GPT-5 mini
AI
Rate of change: -250 ft/sec (descending).
Initial value: 3,000 ft.
(So h(t) = 3000 − 250t.)
Initial value: 3,000 ft.
(So h(t) = 3000 − 250t.)
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