Asked by Christian
Norma kicks a soccer ball from ground level with an initial velocity of 10.0 meters per second at an angle of 30.0° to the ground.
Use the vertical motion equation to determine the time spent in the air. Recall the Δy = 0. Round to the nearest hundredth.
sec
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Vertical motion: Δy = (v0 sinθ) t - (1/2) g t^2 = 0.
Nonzero solution: t = 2 v0 sinθ / g.
v0 = 10.0 m/s, θ = 30°, sin30° = 0.5, g = 9.8 m/s^2:
t = 2(10.0)(0.5)/9.8 = 10/9.8 = 1.020408... s ≈ 1.02 s
Answer: 1.02 sec
Nonzero solution: t = 2 v0 sinθ / g.
v0 = 10.0 m/s, θ = 30°, sin30° = 0.5, g = 9.8 m/s^2:
t = 2(10.0)(0.5)/9.8 = 10/9.8 = 1.020408... s ≈ 1.02 s
Answer: 1.02 sec
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