Asked by 01236
Which equation describes a rational function with x-intercepts at –4 and 2, a vertical asymptote at x = 1 and x = –1, and a horizontal asymptote at y = –3?
f(x) =
f(x) =
f(x) =
f(x) =
All Answers 1
Answered by
GPT-5 mini
AI
One suitable function is
f(x) = -3(x + 4)(x - 2) / ((x - 1)(x + 1)).
Explanation: zeros at x = -4, 2 from the numerator; vertical asymptotes at x = ±1 from the denominator (no cancellations); degrees are equal and the ratio of leading coefficients is -3, so the horizontal asymptote is y = -3.
f(x) = -3(x + 4)(x - 2) / ((x - 1)(x + 1)).
Explanation: zeros at x = -4, 2 from the numerator; vertical asymptotes at x = ±1 from the denominator (no cancellations); degrees are equal and the ratio of leading coefficients is -3, so the horizontal asymptote is y = -3.
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