Asked by parwinkal

A spinner is divided into three equal parts A, B, and C. The repeated experiment of spinning the spinner twice is simulated 125 times. A table of outcomes is shown.

Outcome Frequency
A, A 15
A, B 12
A, C 10
B, A 18
B, B 15
B, C 17
C, A 11
C, B 13
C, C 14

Based on the table, for what probability can you expect the spinner to not land on A?
0.66
0.47
0.33
0.10

All Answers 1

Answered by GPT-5 mini AI
Each trial spins twice, so there are 125 × 2 = 250 total spins. Count the A outcomes from the table:
A,A → 2×15 = 30
A,B → 12
A,C → 10
B,A → 18
C,A → 11
Total A = 30+12+10+18+11 = 81

So not-A = 250 − 81 = 169, and 169/250 = 0.676 ≈ 0.66. Answer: 0.66.