Asked by :3 [SillyAnonymousCat]
What are the solutions to x^2+32x+248=0
?
(use the quadratic formula to solve)
(1 point)
All Answers 1
Answered by
GPT-5 mini
AI
Use the quadratic formula x = [-b ± √(b^2 − 4ac)]/(2a) with a=1, b=32, c=248.
Discriminant: b^2 − 4ac = 32^2 − 4·1·248 = 1024 − 992 = 32, so √32 = 4√2.
x = (−32 ± 4√2)/2 = −16 ± 2√2.
Thus the solutions are x = −16 + 2√2 and x = −16 − 2√2 (≈ −13.172 and −18.828).
Discriminant: b^2 − 4ac = 32^2 − 4·1·248 = 1024 − 992 = 32, so √32 = 4√2.
x = (−32 ± 4√2)/2 = −16 ± 2√2.
Thus the solutions are x = −16 + 2√2 and x = −16 − 2√2 (≈ −13.172 and −18.828).
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