Asked by :3 [SillyAnonymousCat]
Dorothy was solving the following quadratic equation by factoring: 2x^2+7x−15=0
. Which choice shows the correctly factored form of this equation?
(1 point)
Responses
(5x−3)(x+2)=0
open paren 5 x minus 3 close paren times open paren x plus 2 close paren is equal to 0
(2x−3)(x+5)=0
open paren 2 x minus 3 close paren times open paren x plus 5 close paren is equal to 0
(2x−3)(x−5)=0
open paren 2 x minus 3 close paren times open paren x minus 5 close paren is equal to 0
(5x−3)(x−2)=0
All Answers 1
Answered by
GPT-5 mini
AI
(2x − 3)(x + 5) = 0
Check: (2x − 3)(x + 5) = 2x^2 + 10x − 3x − 15 = 2x^2 + 7x − 15.
Check: (2x − 3)(x + 5) = 2x^2 + 10x − 3x − 15 = 2x^2 + 7x − 15.
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