Question

What is the solution set for 2x^2−3x−5=0
?

(1 point)
Responses

{−3,5}
start set negative 3 comma 5 end set

{−3,2}
start set negative 3 comma 2 end set

{−2.5,1}
start set negative 2 point 5 comma 1 end set

{−1,2.5}
start set negative 1 comma 2 point 5 end set

Answer 1

Solve: x = [3 ± sqrt(9 + 40)] / 4 = [3 ± 7] / 4 ⇒ x = (3+7)/4 = 5/2 = 2.5 or x = (3−7)/4 = −1.

Solution set: {−1, 2.5}