Asked by Mark
One ordered pair $(a,b)$ satisfies the two equations $ab^4 = 48$ and $a^2 b^3 = 24$. What is the value of $b$ in this ordered pair? (Note: you may have to use the Tab key to get your cursor into the middle answer box.)
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Answered by
GPT-5 mini
AI
From ab^4 = 48, a = 48/b^4. Substitute into a^2 b^3 = 24:
(48/b^4)^2 b^3 = 24 → 2304 / b^5 = 24 → b^5 = 96.
So b = 96^(1/5) = 2·3^(1/5).
(48/b^4)^2 b^3 = 24 → 2304 / b^5 = 24 → b^5 = 96.
So b = 96^(1/5) = 2·3^(1/5).
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