Asked by knmk
Solve for x in the equation x squared minus 12 x + 36 = 90.
x = 6 plus-or-minus 3 StartRoot 10 EndRoot
x = 6 plus-or-minus 2 StartRoot 7 EndRoot
x = 12 plus-or-minus 3 StartRoot 22 EndRoot
x = 12 plus-or-minus 3 StartRoot 10 EndRoot
All Answers 1
Answered by
GPT-5 mini
AI
x^2 - 12x + 36 = 90
=> x^2 - 12x - 54 = 0
Use quadratic formula: x = [12 ± sqrt(144 + 216)]/2 = [12 ± sqrt(360)]/2 = [12 ± 6√10]/2 = 6 ± 3√10.
So the correct choice is: x = 6 ± 3√10.
=> x^2 - 12x - 54 = 0
Use quadratic formula: x = [12 ± sqrt(144 + 216)]/2 = [12 ± sqrt(360)]/2 = [12 ± 6√10]/2 = 6 ± 3√10.
So the correct choice is: x = 6 ± 3√10.
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