Asked by shawda
Choose the function that represents the data in the table.
f(x) = x200 – 7
f(x) = 200x – 7
f(x) = 200x2 – 7
f(x) = 200x – 7
All Answers 1
Answered by
GPT-5 mini
AI
I don't see the table — could you paste the x and f(x) values?
Meanwhile, here is a quick way to tell which formula fits: evaluate each candidate at a couple of x-values from the table and compare.
Evaluate at x = 0, 1, 2:
- f(x) = x^200 − 7:
- f(0) = 0^200 − 7 = −7
- f(1) = 1 − 7 = −6
- f(2) = 2^200 − 7 (an enormous number)
- f(x) = 200x − 7:
- f(0) = −7
- f(1) = 193
- f(2) = 393
- f(x) = 200x^2 − 7:
- f(0) = −7
- f(1) = 193
- f(2) = 200·4 − 7 = 793
Compare these values to the table entries. If f(1)=193 and f(2)=393 the linear 200x−7 is correct; if f(1)=193 and f(2)=793 the quadratic 200x^2−7 is correct; if f(1)=−6 (and f(2) is astronomically large) the x^200−7 is correct.
Send the table values and I’ll pick the exact function.
Meanwhile, here is a quick way to tell which formula fits: evaluate each candidate at a couple of x-values from the table and compare.
Evaluate at x = 0, 1, 2:
- f(x) = x^200 − 7:
- f(0) = 0^200 − 7 = −7
- f(1) = 1 − 7 = −6
- f(2) = 2^200 − 7 (an enormous number)
- f(x) = 200x − 7:
- f(0) = −7
- f(1) = 193
- f(2) = 393
- f(x) = 200x^2 − 7:
- f(0) = −7
- f(1) = 193
- f(2) = 200·4 − 7 = 793
Compare these values to the table entries. If f(1)=193 and f(2)=393 the linear 200x−7 is correct; if f(1)=193 and f(2)=793 the quadratic 200x^2−7 is correct; if f(1)=−6 (and f(2) is astronomically large) the x^200−7 is correct.
Send the table values and I’ll pick the exact function.
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