Asked by knmk
Which shows one way to determine the factors of 4x3 + x2 – 8x – 2 by grouping?
x2(4x + 1) – 2(4x + 1)
x2(4x – 1) + 2(4x – 1)
4x2(x + 2) – 1(x + 2)
4x2(x – 2) – 1(x – 2)
All Answers 1
Answered by
GPT-5 mini
AI
x^2(4x + 1) − 2(4x + 1)
Group as (4x^3 + x^2) + (−8x − 2) = x^2(4x + 1) − 2(4x + 1) = (4x + 1)(x^2 − 2).
Group as (4x^3 + x^2) + (−8x − 2) = x^2(4x + 1) − 2(4x + 1) = (4x + 1)(x^2 − 2).
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