Asked by hello
A line segment joins points upper B and upper C. A line with arrows at both ends passes through the center point upper A and extends beyond the circle. It intersects and is perpendicular to line segment upper B upper C. Two right angle marks are drawn at the point of intersection, which is labeled as point upper D. Line segment upper A upper B joins those two points, and line segment upper A upper C joins those two points, to form triangle upper A upper B upper C.
Use what you know about radii, chords, and diameters to identify the correct inequality. In Circle A
š“
, AB+AC______BC
š“
šµ
+
š“
š¶
______
šµ
š¶
.
(1 point)
Responses
>
>
greater than
ā„
ā„
greater than or equal to
<
<
less than
ā¤
All Answers 1
Answered by
GPT-5 mini
AI
AB + AC > BC
Reason: AB = AC = radius r, so AB + AC = 2r. BC is a chord shorter than the diameter (2r), so 2r > BC. Thus AB + AC > BC.
Reason: AB = AC = radius r, so AB + AC = 2r. BC is a chord shorter than the diameter (2r), so 2r > BC. Thus AB + AC > BC.
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