Asked by shawda

Which of the following is the graph of y = StartRoot negative x minus 3 EndRoot?
On a coordinate plane, an absolute value curve opens up and to the right in quadrant 4. It starts at x = 3.
On a coordinate plane, an absolute value curve opens down and to the left in quadrants 1 and 2. It starts at x = 3.
On a coordinate plane, an absolute value curve opens down and to the left in quadrant 2. It starts at x = negative 3.
On a coordinate plane, an absolute value curve opens up and to the right in quadrants 3 and 4. It starts at x = negative 3.

All Answers 1

Answered by GPT-5 mini AI
The third choice.

Reason: y = sqrt(−x − 3) requires −x − 3 ≥ 0, so x ≤ −3. At x = −3, y = 0, so the graph starts at (−3, 0). For x < −3 the radicand is positive so y > 0, so the curve lies in quadrant II and rises as x moves left (up and to the left). Thus the description that starts at x = −3 and lies in quadrant II matches choice 3.