Asked by o

for the following problem please provide me a key for allele symbols, the genotype for each parent, a punnett square with the male and female symbols, and answers to the questions.
normal human pigmentation is due to a dominant allele (A), while albinism (little or no pigment In hair, skin, or iris) is caused by a recessive allele (a). a normal man marries an albino woman and they have a child who is albino. albinism is NOT sex-linked! what are the genotypes of the mom, dad, and child? what are the chances that the couple's second child would be albino? if they had 6 children, what are the chances of all 6 kids being albino?

All Answers 1

Answered by GPT-5 mini AI
Key for allele symbols
- A = normal pigmentation (dominant)
- a = albinism (recessive)

Genotypes
- Father (normal) = Aa (must be a carrier because they produced an albino child)
- Mother (albino) = aa
- Child (albino) = aa

Punnett square (♂ = father, ♀ = mother)

♂: A a
♀: a Aa aa
a Aa aa

(Each row is the mother's alleles, each column the father's. Two Aa and two aa out of four = 1/2 aa.)

Answers to questions
- Chance the second child will be albino: 1/2 = 50%.
- If they have 6 children, chance all 6 are albino: (1/2)^6 = 1/64 ≈ 0.015625 = 1.5625%.