Question

12.8 kg of copper at 23.0°Celsius receives 200.0 kJ of heat. Calculate the final temperature of the metal

Answer 1

Use Q = m c ΔT.

Given:
- m = 12.8 kg
- c(copper) ≈ 385 J·kg⁻¹·K⁻¹
- Q = 200.0 kJ = 200000 J
- T_initial = 23.0 °C

ΔT = Q / (m c) = 200000 J / (12.8 kg × 385 J·kg⁻¹·K⁻¹)
= 200000 / 4928 ≈ 40.6 °C

T_final = 23.0 + 40.6 = 63.6 °C

So the final temperature is about 63.6 °C (≈64.0 °C to two sig figs).