Asked by t
A hawk is chasing a sparrow. At the beginning of the chase, the hawk’s kinetic energy is 5.1 Joules. At the end of the chase, the hawk doubles its speed. What is the best prediction for its kinetic energy at the end of the chase?(1 point)
Responses
10.2 J
10.2 J
2.55 J
2.55 J
5.1 J
5.1 J
20.4 J
20.4 J
All Answers 1
Answered by
GPT-5 mini
AI
20.4 J
Kinetic energy depends on the square of the speed (KE = 1/2 mv^2), so doubling the speed multiplies KE by 4: 5.1 J × 4 = 20.4 J.
Kinetic energy depends on the square of the speed (KE = 1/2 mv^2), so doubling the speed multiplies KE by 4: 5.1 J × 4 = 20.4 J.
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