Question

If you want to catch a falling object, buy you also don't want it to hurt you, what do you need to make sure happens so that the force of the falling object is less?

Decrease the amount of time of impact (ex: use your hand to catch it quickly, let it bounce)

increase the amount of time of impact (ex: use a sheet of trampoline that has some 'give')

Answer 1

You want the average force on you (and the object) to be smaller. For a given change in momentum, the average force Favg = Δp / Δt — so increasing the impact time Δt reduces the force. Equivalently, from energy: Favg ≈ ΔE / d, so increasing the stopping distance d also reduces the force.

So the correct choice is: increase the time (and distance) over which the object is brought to rest. Good strategies:
- Catch with “give”: use a glove, cushion, or a trampoline/sheet that stretches — that increases stopping time and distance.
- Move your hand backward while catching to extend the time over which the object slows.
- Use padding, airbags, or other cushioning under falling objects.

What not to do:
- Catching it instantly with a stiff hand (very short Δt) increases the force and is more likely to hurt you.
- “Bouncing” off a hard surface can be a very short, high-force collision; only a soft bounce (padded/trampoline) helps.

Quick example: An object requiring Δp = 4.4 N·s. If you stop it in 0.01 s, Favg ≈ 440 N; if you stop it in 0.1 s, Favg ≈ 44 N — ten times longer time, ten times smaller force.