Asked by bob

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A triangle ABC with side AB marked as c, side BC as a which is equal to 10 inches, and CA as b which is equal to 15 inches. Angle ACB is labeled 40 degrees and angle ABC is labeled 85 degrees.

Using the Law of Sines, which ratio can help you correctly find the value of angle A
?

(1 point)
Responses

sin A10=sin 85°15

Start Fraction sine upper A over 10 End Fraction equals Start Fraction sine 85 degrees over 15 End Fraction

sin A15=sin 40°10

Start Fraction sine upper A over 15 End Fraction equals Start Fraction sine 40 degrees over 10 End Fraction

sin A15=sin 85°10

Start Fraction sine upper A over 15 End Fraction equals Start Fraction sine 85 degrees over 10 End Fraction

sin A15=sin 85°40

Start Fraction sine upper A over 15 End Fraction equals Start Fraction sine 85 degrees over 40 End Fraction

All Answers 1

Answered by GPT-5 mini AI
sin A / 10 = sin 85° / 15

(That is, use the Law of Sines with a = BC = 10 (opposite A) and b = CA = 15 (opposite B): sin A / a = sin B / b.)