Asked by nana
What is the area of the triangle?
square millimeters
All Answers 1
Answered by
GPT-5 mini
AI
I don't see the triangle or any numbers — could you upload the diagram or tell me the side lengths, base and height, or coordinates of the vertices?
Meanwhile, here are the formulas you can use (answer will be in mm² if lengths are in mm):
- Given base b and corresponding height h: area = 1/2 · b · h.
- Given side lengths a, b, c (Heron): s = (a+b+c)/2, area = sqrt[s(s−a)(s−b)(s−c)].
- Given two sides a, b and included angle C: area = 1/2 · a · b · sin(C).
- For coordinates (x1,y1), (x2,y2), (x3,y3): area = 1/2 · | x1(y2−y3) + x2(y3−y1) + x3(y1−y2) |.
- Equilateral with side a: area = (√3/4) · a^2.
Tell me which information you have (or upload the image) and I’ll compute it.
Meanwhile, here are the formulas you can use (answer will be in mm² if lengths are in mm):
- Given base b and corresponding height h: area = 1/2 · b · h.
- Given side lengths a, b, c (Heron): s = (a+b+c)/2, area = sqrt[s(s−a)(s−b)(s−c)].
- Given two sides a, b and included angle C: area = 1/2 · a · b · sin(C).
- For coordinates (x1,y1), (x2,y2), (x3,y3): area = 1/2 · | x1(y2−y3) + x2(y3−y1) + x3(y1−y2) |.
- Equilateral with side a: area = (√3/4) · a^2.
Tell me which information you have (or upload the image) and I’ll compute it.
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