Asked by marisol
A chemical equation can be balanced or unbalanced. Looking at the equation below shows
evidence that proves that this equation is balanced or unbalanced.
Is the equation above balanced? ______________ Explain:
All Answers 1
Answered by
GPT-5 mini
AI
I don't see the chemical equation in your message. Please paste it and I will check it.
In the meantime, here is the quick method you should use to decide if any equation is balanced:
1. List every element appearing in the equation.
2. Count the number of atoms of each element on the reactant side (use coefficients × subscript).
3. Count the number of atoms of each element on the product side.
4. If every element has the same total on both sides, the equation is balanced. If any element differs, it is unbalanced.
Notes:
- Do not change subscripts in formulas (that changes the compound); change coefficients only.
- For polyatomic ions that appear unchanged on both sides, you can count the whole ion once and multiply by the coefficient.
Example 1 (unbalanced -> balanced)
H2 + O2 → H2O
Count: H left 2, right 2; O left 2, right 1 → unbalanced.
Balance by putting coefficient 2 before H2O:
H2 + O2 → 2 H2O becomes 2 H2 + O2 → 2 H2O
Now H: 4 left, 4 right; O: 2 left, 2 right → balanced.
Example 2 (more typical)
Fe + O2 → Fe2O3
Count: Fe left 1, right 2; O left 2, right 3 → unbalanced.
Balance by coefficients: 4 Fe + 3 O2 → 2 Fe2O3
Now Fe: 4 left, 4 right; O: 6 left, 6 right → balanced.
Send the specific equation and I'll show the atom count and state whether it's balanced.
In the meantime, here is the quick method you should use to decide if any equation is balanced:
1. List every element appearing in the equation.
2. Count the number of atoms of each element on the reactant side (use coefficients × subscript).
3. Count the number of atoms of each element on the product side.
4. If every element has the same total on both sides, the equation is balanced. If any element differs, it is unbalanced.
Notes:
- Do not change subscripts in formulas (that changes the compound); change coefficients only.
- For polyatomic ions that appear unchanged on both sides, you can count the whole ion once and multiply by the coefficient.
Example 1 (unbalanced -> balanced)
H2 + O2 → H2O
Count: H left 2, right 2; O left 2, right 1 → unbalanced.
Balance by putting coefficient 2 before H2O:
H2 + O2 → 2 H2O becomes 2 H2 + O2 → 2 H2O
Now H: 4 left, 4 right; O: 2 left, 2 right → balanced.
Example 2 (more typical)
Fe + O2 → Fe2O3
Count: Fe left 1, right 2; O left 2, right 3 → unbalanced.
Balance by coefficients: 4 Fe + 3 O2 → 2 Fe2O3
Now Fe: 4 left, 4 right; O: 6 left, 6 right → balanced.
Send the specific equation and I'll show the atom count and state whether it's balanced.
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