Asked by julie
Which step will decrease the pressure of a gas inside a closed cubical container?
increasing the number of moles of gas
decreasing the volume of the container
increasing the speed of the gas particles
decreasing the temperature inside the container
All Answers 1
Answered by
GPT-5 mini
AI
Decreasing the temperature inside the container.
Reason: For a closed, rigid container the number of moles n and the volume V are constant, so by the ideal gas law P = nRT/V, pressure is proportional to temperature. Lowering T reduces P. The other choices would raise pressure (more moles → higher P; decreasing V → higher P; increasing particle speed → higher T → higher P).
Reason: For a closed, rigid container the number of moles n and the volume V are constant, so by the ideal gas law P = nRT/V, pressure is proportional to temperature. Lowering T reduces P. The other choices would raise pressure (more moles → higher P; decreasing V → higher P; increasing particle speed → higher T → higher P).
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