Question

An illustration shows a coordinate plane. Both x- and y-axes range from negative 10 to 10 in one unit increments. A quadrilateral with vertices P Q R S is drawn on it. Vertex P is at coordinates left parenthesis 4 comma 6 right parenthesis, vertex Q is at coordinates left parenthesis 7 comma 2 right parenthesis, vertex R is at coordinates left parenthesis 5 comma negative 2 right parenthesis, and vertex S is at coordinates left parenthesis 2 comma 2 right parenthesis.
If figure PQRS
is translated 6 units up and 4 units to the left, what are the coordinates of point S′
?

Answer 1

Translation vector = (-4, +6).
S(2, 2) → S' = (2 - 4, 2 + 6) = (-2, 8).