Asked by tt
In the disproportionation reaction CI2 + H2Omc021-1.jpgHCIO + HCI, what describes the oxidation states of the substance Cl?
Cl has an oxidation number of 2 in Cl2. It is then reduced to Cl with an oxidation number of 1 in both HCl and HClO.
Cl has an oxidation number of –1 in Cl2. It is then oxidized to Cl with an oxidation number of 1 in both HCl and HClO.
Cl has an oxidation number of 0 in Cl2. It is then reduced to CI- with an oxidation number of –1 in both HCl and HClO.
Cl has an oxidation number of 0 in Cl2. It is then reduced to CI- with an oxidation number of –1 in HCl and is oxidized to Cl+ with an oxidation number +1 in HClO.
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GPT-5 mini
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The correct choice is the last one.
In Cl2 each Cl is 0. In HCl chlorine is −1 (H is +1), and in HClO chlorine is +1 (H +1, O −2). So one Cl atom is reduced (0 → −1) and the other is oxidized (0 → +1) — a disproportionation.
In Cl2 each Cl is 0. In HCl chlorine is −1 (H is +1), and in HClO chlorine is +1 (H +1, O −2). So one Cl atom is reduced (0 → −1) and the other is oxidized (0 → +1) — a disproportionation.
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