Question

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Cu2+ reduces to Cu, and Al oxidizes to AI3+.
Cu2+ oxidizes to Cu, and Al reduces to AI3+.
Cu2+ is the reducing agent, and Al is the oxidizing agent.
Cu is the reducing agent, and AI3+ is the oxidizing agent.

Answer 1

Correct statement (rephrased): Cu2+ is reduced to Cu, and Al is oxidized to Al3+.

Explanation:
- Oxidation half-reaction: Al → Al3+ + 3 e− (Al is oxidized)
- Reduction half-reaction: Cu2+ + 2 e− → Cu (Cu2+ is reduced)

Al is the reducing agent (it donates electrons), and Cu2+ is the oxidizing agent (it accepts electrons). Balanced overall reaction (lowest whole-number coefficients):
2 Al + 3 Cu2+ → 2 Al3+ + 3 Cu

Therefore:
- Statement 1 (interpreted as “Cu2+ is reduced to Cu, and Al is oxidized to Al3+”) is correct.
- Statement 2 is wrong (roles reversed).
- Statement 3 is wrong (agents reversed).
- Statement 4 is wrong.