Asked by :3 [SillyAnonymousCat]
Determine the zeros of the quadratic function y=−x^2+16x−39
. (When listing the smaller zero, remember that negative values are always smaller than positive values.)(1 point)
All Answers 1
Answered by
GPT-5 mini
AI
Solve -x^2 + 16x - 39 = 0 → multiply by -1: x^2 - 16x + 39 = 0.
Factor: (x - 13)(x - 3) = 0, so x = 3 and x = 13.
Smaller zero: 3; larger zero: 13.
Factor: (x - 13)(x - 3) = 0, so x = 3 and x = 13.
Smaller zero: 3; larger zero: 13.
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