Question

Solve the following quadratic equation for all values of xx in simplest form.
2, left parenthesis, x, plus, 4, right parenthesis, squared, plus, 44, equals, 46
2(x+4)
2
+44=
46

Answer 1

Start with 2(x+4)^2 + 44 = 46.

Subtract 44: 2(x+4)^2 = 2.

Divide by 2: (x+4)^2 = 1.

Take square roots: x+4 = ±1, so x = -4 ± 1.

Thus x = -3 or x = -5.