The hydroxyl radical (OH) is an important oxidizing agent in the atmosphere. At 298 K the rate constant for the reaction of OH with benzene is 1.24 10-12 cm3 molecule -1 s -1. Calculate the value of the rate constant in L mol -1 s -1.
This is what I tried:
1.24*10^-12 cm3/ molecule -1 s -1 = 0.001 L/1 cm3
=1.24E-15 L/molecule s* 6.022 x 10E23 molecules/mol
= 7.46 E8 L/mol s
Is this process correct?
4 answers
ohh nvm I got it!!
yes
how did you do this?
i second jwu! i would like to know how to figured it out.