Asked by Mario
If a circuit has a 3.9 k ohms resistor and a 5 uF capacitor, find the current flow in the circuit at 0.005 seconds, if the maximum current flow in the circuit is 1.5 mA.
Answers
Answered by
Henry
RC = 3.9k * 5 uF = 19.5 ms = 0.0195 s.
t / RC = 5 ms / 19.5 ms = 0.256 ms =
0.000256 s.
i = i max / e^(t/RC),
i = 1.5 ma / e^0.256 = 1.5 / 1.292 =
1.16 mA @ 5 ms (0.005 s).
s = Seconds.
ms = milliseconds.
t / RC = 5 ms / 19.5 ms = 0.256 ms =
0.000256 s.
i = i max / e^(t/RC),
i = 1.5 ma / e^0.256 = 1.5 / 1.292 =
1.16 mA @ 5 ms (0.005 s).
s = Seconds.
ms = milliseconds.
There are no AI answers yet. The ability to request AI answers is coming soon!