Question

Identify if the equation is exponential growth or decay

f (x) = 100(0.83)^x
f (x) = 3,567(1.28)^x
f (x) = 1,000(0.08)^x
f (x) = 35(1.05)^x

Answer 1

- f(x) = 100(0.83)^x — exponential decay (base 0.83 < 1; about a 17% decrease per unit)
- f(x) = 3,567(1.28)^x — exponential growth (base 1.28 > 1; about a 28% increase per unit)
- f(x) = 1,000(0.08)^x — exponential decay (base 0.08 < 1; about a 92% decrease per unit)
- f(x) = 35(1.05)^x — exponential growth (base 1.05 > 1; about a 5% increase per unit)