Question
A 50 kg crate is initially at rest on a plane inclined at an angle of 30 degrees to the horizontal. A man then pulls the crate up the incline via a rope that is parallel to the inclined plane. The tension that the man imparts to the rope is 100 N, and the coefficient of kinetic friction between the block and the surface is 0.50. A. What is the acceleration of the block? B. How long will it take the crate to travel 2.0m up the incline?
Answers
bobpursley
The weight of the crate down the hill is mgSinTheta.
frictionforce= mg*mu*CosTheta
so NetForce= 100-mgSinTheta-mu*mgCosTheta
and that has to equal mass*a
frictionforce= mg*mu*CosTheta
so NetForce= 100-mgSinTheta-mu*mgCosTheta
and that has to equal mass*a
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